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At 40 c,the value of Kw is 2.92

10-14.calculate the [H+] and [OH-] of pure water at 40 c.

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This question has been answered before.

"the value of Kw is 2.92
10-14" ?? units are missing

Given that [H+][OH-]=Kw and that

[H+] = [OH-] for pure water

then

[H+][OH-]=[H+][H+]=2.92 x 10^-14

[H+]^2= 2.92 x 10^-14

[H+] = sqrt(2.92 x 10^-14)

but this is missing the units.
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