Asked by ana
a gate 6m wide requires a force of 5.2 kg.wt. applied at the end to open it. what force would have to be applied (A) at the middle and (B) at 1.5m from the hinges, to open it?
Answers
Answered by
Damon
the product of force and lever arm must be constant
F * x = 5.2 * g * 6 = 31.2 g
so A
F * 3 = 31.2 g
F = 10.4 g
B
F * 1.5 = 31.2 g
F = 20.8 g
The g is because I assume your mass is hanging from a pulley pulling on the gate. Kg is mass, not force.
F * x = 5.2 * g * 6 = 31.2 g
so A
F * 3 = 31.2 g
F = 10.4 g
B
F * 1.5 = 31.2 g
F = 20.8 g
The g is because I assume your mass is hanging from a pulley pulling on the gate. Kg is mass, not force.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.