Asked by Tracy
Evaluate the integral of
xe^2x(dx)
A. (1/6)(x^2)(e^3x)+C
B. (1/2)(xe^2x)-(1/2)(e^2x)+C
C. (1/2)(xe^2x)-(1/4)(e^2x)+C
D. (1/2)(x^2)-(1/8)(e^4x)+C
xe^2x(dx)
A. (1/6)(x^2)(e^3x)+C
B. (1/2)(xe^2x)-(1/2)(e^2x)+C
C. (1/2)(xe^2x)-(1/4)(e^2x)+C
D. (1/2)(x^2)-(1/8)(e^4x)+C
Answers
Answered by
Damon
u dv = u v - int v du
u = x
du = dx
dv = e^(2x) dx
v = (1/2) e^(2x)
so
int x e^(2x) dx = (x/2)e^(2x)- int (1/2)e^(2x) dx
= (x/2)e^(2x)- (1/4)e^(2x) +c
so I think C.
u = x
du = dx
dv = e^(2x) dx
v = (1/2) e^(2x)
so
int x e^(2x) dx = (x/2)e^(2x)- int (1/2)e^(2x) dx
= (x/2)e^(2x)- (1/4)e^(2x) +c
so I think C.
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