Question
what is the orthocenter of triangle with the vertices of X(-11,0),
Y(-11,-8), Z(-1,-4)?
Y(-11,-8), Z(-1,-4)?
Answers
Steve
Let Zz be the altitude from Z to XY. This is the line y = -4 since XY is vertical.
Let Xx be the altitude from X to YZ. This is a line through (-11,0) with slope -5/2.
(y-0)/(x+11) = -5/2
y = -5/2 x - 55/2
Where do the lines intersect?
-5/2 x - 55/2 = -4
-5x - 55 = -8
-5x = 47
x = -47/5
So, the orthocenter is at (-9.4,-4)
I'll let you verify by using the other altitude from Y to XZ.
Let Xx be the altitude from X to YZ. This is a line through (-11,0) with slope -5/2.
(y-0)/(x+11) = -5/2
y = -5/2 x - 55/2
Where do the lines intersect?
-5/2 x - 55/2 = -4
-5x - 55 = -8
-5x = 47
x = -47/5
So, the orthocenter is at (-9.4,-4)
I'll let you verify by using the other altitude from Y to XZ.
Melanie
Hey Steve,
Thanks....but how could it be -4?
Thanks....but how could it be -4?
Melanie
never mind...i understand