Asked by Melanie
what is the orthocenter of triangle with the vertices of X(-11,0),
Y(-11,-8), Z(-1,-4)?
Y(-11,-8), Z(-1,-4)?
Answers
Answered by
Steve
Let Zz be the altitude from Z to XY. This is the line y = -4 since XY is vertical.
Let Xx be the altitude from X to YZ. This is a line through (-11,0) with slope -5/2.
(y-0)/(x+11) = -5/2
y = -5/2 x - 55/2
Where do the lines intersect?
-5/2 x - 55/2 = -4
-5x - 55 = -8
-5x = 47
x = -47/5
So, the orthocenter is at (-9.4,-4)
I'll let you verify by using the other altitude from Y to XZ.
Let Xx be the altitude from X to YZ. This is a line through (-11,0) with slope -5/2.
(y-0)/(x+11) = -5/2
y = -5/2 x - 55/2
Where do the lines intersect?
-5/2 x - 55/2 = -4
-5x - 55 = -8
-5x = 47
x = -47/5
So, the orthocenter is at (-9.4,-4)
I'll let you verify by using the other altitude from Y to XZ.
Answered by
Melanie
Hey Steve,
Thanks....but how could it be -4?
Thanks....but how could it be -4?
Answered by
Melanie
never mind...i understand
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.