Asked by Amber

A chemist needs to mix a solution containing 30% insecticide with a solution containg 50% insecticide to make 200L of a solution that 42% insecticide. How much of each solution should she use?

dealing with- graphing, subst., and elimin.
Answered by Reiny
let x L represent the volume of the 30% solution, then 200 - x L would be the 50% solution

then...

.3x + .5(200-x) = .42(200)
solve....