Ask a New Question

Prove the law of sines for triangle ABC i.e sinA/a=sinB/b=sinC/c.0 please help me!!!

1 answer

It is not=0. Please help me!

Similar Questions

Prove that in any triangle ABC Sin2A+Sin2B+Sin2C/SinA+SinB+SinC=8Sin(A/2)Sin(B/2)Sin(C/2)
1. 1 answer
Prove That Sin2A+ Sin2B +SIN2C/sinA+SINB+SINC=8sinA/sinB/2COSC/2
1. 1 answer
If A+B+C=^(^=180) prove thatsinA + sinB - sinC = 4sinA/2 sinB/2 cosC/2
1. 2 answers
if cos(B-C)+cos(C-A)+cos(A-B)=-3/2 then prove that cosA+cosB+cosC=O and sinA+sinB+sinC=O after that prove that
1. 1 answer

more similar questions