Asked by vmu
SOLVE THE EQUATION FOR Z
Z divied by Z+2+i=3+i
Z divied by Z+2+i=3+i
Answers
Answered by
Reiny
Z/(Z+2+i) = 3+i
Z = 3Z + Zi + 6 + 2i + 3i + i^2
Z - 3Z - iZ = i^2 + 5i + 6
Z(-2-i) = i^2 + 5i + 6
Z = -(i^2 + 5i + 6)/(i+2)
Z = 3Z + Zi + 6 + 2i + 3i + i^2
Z - 3Z - iZ = i^2 + 5i + 6
Z(-2-i) = i^2 + 5i + 6
Z = -(i^2 + 5i + 6)/(i+2)
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