Asked by amar
An aeroplane when 6000 m high passes vertically above another plane at an instant when their angles of elevation at the same observing point are 60° and 45° respectively. How many meters higher is the one than the other?
Answers
Answered by
Reiny
Draw a vertical line with A the top plane, B the lower plane and C the point on the ground below the planes.
ABC is a straight line.
Let D be the position of the observer on the ground
Let AB = x m
We know:
BC = 6000
∠BDC = 45°, so DC = 6000
∠DAC = 60°
in ∆ADC, tan 60° = (x+6000)/6000
(x+6000)/6000 = √3
x+6000 = 6000√3
x = 6000√3 - 6000 = 4392.3 m
ABC is a straight line.
Let D be the position of the observer on the ground
Let AB = x m
We know:
BC = 6000
∠BDC = 45°, so DC = 6000
∠DAC = 60°
in ∆ADC, tan 60° = (x+6000)/6000
(x+6000)/6000 = √3
x+6000 = 6000√3
x = 6000√3 - 6000 = 4392.3 m
Answered by
Rakshit Panwar
It was useless
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.