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Write the equilibrium constant expression, K, for each of the following reactions. Where appropriate, designate the K as Ksp. 2...Asked by Kevin
(Re-post)
Write the equilibrium constant expression, K, for each of the following reactions. Where appropriate, designate the K as Ksp.
2H2(g) + O2(g)<-->2H2O(g)
2Hg(l) + Cl2(g) <-->Hg2Cl2(s)
Write the equilibrium constant expression, K, for each of the following reactions. Where appropriate, designate the K as Ksp.
2H2(g) + O2(g)<-->2H2O(g)
2Hg(l) + Cl2(g) <-->Hg2Cl2(s)
Answers
Answered by
DrBob222
What's your problem with this? What do you not understand.
Answered by
Kevin
well for the first one, should the answer be... K = [H2O]^2
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[H2]^2 + [O2]
or should it just be... K = [H2O]^2?
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[H2]^2 + [O2]
or should it just be... K = [H2O]^2?
Answered by
DrBob222
Your first one is correct except there is no + sign in the denominator. It's supposed to be products over reactants, each raised to the power indicated by the coefficient, so you can't leave out the reactants.
(H2O)^2/(H2)^2(O2)
The second one is
1/(Cl2).
Hg2Cl2 is not included because it's a solid and that's the natural state for it. Hg is not included because that is a liquid and that's the natural state for it. Before you ask about H2O in the first one, H2O(l) would be in the natural state BUT you note that is H2O(g).
(H2O)^2/(H2)^2(O2)
The second one is
1/(Cl2).
Hg2Cl2 is not included because it's a solid and that's the natural state for it. Hg is not included because that is a liquid and that's the natural state for it. Before you ask about H2O in the first one, H2O(l) would be in the natural state BUT you note that is H2O(g).
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