Asked by Anonymous
                Use the equations with the enthalpy information given below to calculate the ÄH° for the reaction: 
S(s) + O2(g) --> SO2(g)
S(s) + 3/2 O2(g) --> SO3(g)
ÄH° = -395kJ
2 SO2(g) + O2(g) --> 2 SO3(g)
ÄH° = -198.2 kJ
            
        S(s) + O2(g) --> SO2(g)
S(s) + 3/2 O2(g) --> SO3(g)
ÄH° = -395kJ
2 SO2(g) + O2(g) --> 2 SO3(g)
ÄH° = -198.2 kJ
Answers
                    Answered by
            DrBob222
            
    1) S(s) + 3/2 O2(g) --> SO3(g)
ÄH° = -395kJ
2) 2SO2(g) + O2(g) --> 2 SO3(g)
ÄH° = -198.2 kJ
Multiply equation 1 by 2 and add to the reverse of equation 2. delta H values are multiplied by any multipliers and delta H values change their sign when the reaction is reversed.
When you finish you will have the right equation EXCEPT it will be just twice what you want; therefore, divide everything by 2 including the delta H value.
    
ÄH° = -395kJ
2) 2SO2(g) + O2(g) --> 2 SO3(g)
ÄH° = -198.2 kJ
Multiply equation 1 by 2 and add to the reverse of equation 2. delta H values are multiplied by any multipliers and delta H values change their sign when the reaction is reversed.
When you finish you will have the right equation EXCEPT it will be just twice what you want; therefore, divide everything by 2 including the delta H value.
                    Answered by
            mdc wolfson campus
            
    How much heat is evolved when 320 g of SO2 is burned according to the chemical equation shown below? 
    
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