Asked by Anonymous
Two Planes approach each other head-on. One plane has a speed of 800 km/h and the other has a speed of 900 km/h and they spot each other when they are initially 15 km apart. How much time in seconds do the pilots have to take evasive action?
Answers
Answered by
Damon
they are headed toward each other at
(800+900) /(3600) km/s
= .4722 km/second
15 km = .4722 t
t = 31.8 seconds
(800+900) /(3600) km/s
= .4722 km/second
15 km = .4722 t
t = 31.8 seconds
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