qcal x delta T = 0.1619g*26.43 kJ/g
Solve for qcal.
qvanillin = qcal x delta T
qvanillin/0.1510 = ?kJ/g
The combustion of 0.1619 g benzoic acid increases the temperature of a bomb calorimeter by 2.77°C. Calculate the heat capacity of this calorimeter. (The energy released by combustion of benzoic acid is 26.42 kJ/g.)
kJ/°C
A 0.1510 g sample of vanillin (C8H8O3) is then burned in the same calorimeter, and the temperature increases by 3.25°C. What is the energy of combustion per gram of vanillin?
kJ/g
What is the energy of combustuin per mole of vanillin?
kJ/mol
1 answer