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Anonymous
what is the vert. comp. of vector with magnitude 88.5m/s and whose horiz. comp. is 75.4m/s? what is the direct. of this vector?
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Answered by
Damon
cos theta = 75.4/88.5
theta = cos^-1 .852
theta = 31.57 degrees from horizonal
vertical component = 88.5 sin 31.57
=46.33
Answered by
Anonymous
thanks, i figured it out
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