Asked by muma
Simplify:
(a) 4ã7 (2ã3 +3ã6 -ã7 )
(b) (3ã7 -ã2 )squared
(c) (16ã24)/(4ã96)
(d) 7/(ã20 ) - 4/(ã12)
(e) (3ã2)/(ã12) - (5ã3)/(ã8 )
Answers
Answered by
Reiny
I will assume your ã is supposed to be a √
To do these, you should know the basic laws for radicals, such as
√a x √b = √(ab) etc.
I will do the first and last, give the others a shot
a)
4√7(2√3 + 3√6 - √7)
= 8√21 + 12√42 - 4√49
= 8√21 + 12√42 - 28
e)
3√2/√12 - 5√3/√8
= 3√2/(2√3) - 5√3/(2√2)
= 3√2/(2√3)<b>(√3/√3)</b> - 5√3/(2√2)<b>(√2/√2)</b>
= 3√6/6 - 5√6/4
= √6/2 - 5√6/4
= 2√6/4 - 5√6/4
= -3√6/4
To do these, you should know the basic laws for radicals, such as
√a x √b = √(ab) etc.
I will do the first and last, give the others a shot
a)
4√7(2√3 + 3√6 - √7)
= 8√21 + 12√42 - 4√49
= 8√21 + 12√42 - 28
e)
3√2/√12 - 5√3/√8
= 3√2/(2√3) - 5√3/(2√2)
= 3√2/(2√3)<b>(√3/√3)</b> - 5√3/(2√2)<b>(√2/√2)</b>
= 3√6/6 - 5√6/4
= √6/2 - 5√6/4
= 2√6/4 - 5√6/4
= -3√6/4
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