Asked by Dakota
Use Newton's method to approximate the indicated root of the equation correct to six decimal places.
The positive root of
3sinx = x^2
The positive root of
3sinx = x^2
Answers
Answered by
Steve
A little perl program for Newton's Method reveals the solution for x^2 - 3sinx = 0:
1: 2.0000000 = 1.2721077
2: 1.7576218 = 0.1414378
3: 1.7228915 = 0.0029877
4: 1.7221255 = 0.0000015
5: 1.7221251 = 0.0000000
1: 2.0000000 = 1.2721077
2: 1.7576218 = 0.1414378
3: 1.7228915 = 0.0029877
4: 1.7221255 = 0.0000015
5: 1.7221251 = 0.0000000
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