Question

a 60 kg student jumps from a table 1.2m high. When his feet hit the floor he bends his knees so that the stopping time is .06s. What is the average force that the floor exerts on his body in order to stop him?

Answer 1

mgh=1/2 m v^2

velocity at impact= sqrt (2gh)

force*time= mass*velocity
solve for force