Asked by ali
A student measures 0.2452 g of a monoprotic solid acid, and dissolves the solid in water to make 100.0 mL of solution. the entire solution is titrated to a phenolphthalein endpoint with 45.06mL of 0.1725M KOH.
A. what is the molarity of the acid solution?
B. what is the molar mass of the solid acid?
A. what is the molarity of the acid solution?
B. what is the molar mass of the solid acid?
Answers
Answered by
DrBob222
moles KOH = M KOH x L KOH = ?
moles unknown acid = moles KOH since the acid is monoprotic.
moles acid = grams/molar mass
Solve for molar mass.
moles unknown acid = moles KOH since the acid is monoprotic.
moles acid = grams/molar mass
Solve for molar mass.
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