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How do you simplify the radical 4sqrt(128 n^8)
13 years ago

Answers

Anonymous
128 = 2 * 64

n ^ 8 = ( n ^ 4 ) ^ 2


4 sqrt ( 128 * n ^ 8 ) =

4 sqrt[ 64 * 2 * ( n ^ 4 ) ^ 2 ]



sqrt ( 64 ) = 8

sqrt [ ( n ^ 4 ) ^ 2 ] = n ^ 4


4 sqrt[ 64 * 2 * ( n ^ 4 ) ^ 2 ] =

4 * 8 * n ^ 4 * sqrt ( 2 )=

32 n ^ 4 sqrt (2 )
13 years ago
Anonymous
2n^2 ^4squareroot 8
9 years ago

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