How do you simplify the radical 4sqrt(128 n^8)

Answer 1

128 = 2 * 64

n ^ 8 = ( n ^ 4 ) ^ 2

4 sqrt ( 128 * n ^ 8 ) =

4 sqrt[ 64 * 2 * ( n ^ 4 ) ^ 2 ]

sqrt ( 64 ) = 8

sqrt [ ( n ^ 4 ) ^ 2 ] = n ^ 4

4 sqrt[ 64 * 2 * ( n ^ 4 ) ^ 2 ] =

4 * 8 * n ^ 4 * sqrt ( 2 )=

32 n ^ 4 sqrt (2 )

Answer 2

2n^2 ^4squareroot 8