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The mean score on a Math exam was 50% and the standard deviation was 10%. Assume the results were normally distributed.
(a) What percent of students earned a score between 50% and 70%?
( /2)
13 years ago

Answers

PsyDAG
Z = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to Z score. Change to percentage.
13 years ago

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