(Mass flow rate)*(energy release per mass)
= g*H* (5.4*10^4 kg/s)
= 20.1 Megawatts
Water flows over a section of a waterfall at the rate of 5.4 104 kg/s and falls 38 m. How much power is generated by the falling water?
4 answers
20130120
I don't understand how you got 20.1. What did you divide that first number by?
dr wellos is a genius