Asked by Jake
Verify tanxsin2x = 2-2cos^2x
Answers
Answered by
Anonymous
tan(x) = sin(x) / cos(x)
sin(2x) = 2 * sin(x) * cos(x)
tan(x)*sin(2x) = [sin(x) / cos(x)] * 2 * sin(x) * cos(x) =
2 sin(x) * sin(x) = 2 sin^2(x)
sin^2(x) + cos^2(x) = 1
sin^(x) = 1 - cos^2(x)
2 sin^2(x) = 2 * [ 1 - cos^2(x) ] = 2 - 2 * cos^2(x)
sin(2x) = 2 * sin(x) * cos(x)
tan(x)*sin(2x) = [sin(x) / cos(x)] * 2 * sin(x) * cos(x) =
2 sin(x) * sin(x) = 2 sin^2(x)
sin^2(x) + cos^2(x) = 1
sin^(x) = 1 - cos^2(x)
2 sin^2(x) = 2 * [ 1 - cos^2(x) ] = 2 - 2 * cos^2(x)