Asked by Anonymous
The average score of all golfers for a particular course has a mean of 73 and a standard deviation of 3. Suppose
36 golfers played the course today. Find the probability that the average score of the 36 golfers exceeded 74.
36 golfers played the course today. Find the probability that the average score of the 36 golfers exceeded 74.
Answers
Answered by
PsyDAG
Z = (mean1 - mean2)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.
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