Asked by lindsay
A survey was conducted to measure the number of hours per week adults spend on home
computers. In the survey, the number of hours was normally distributed, with a mean of 8
hours and a standard deviation of 1 hour. A survey participant is randomly selected. Find the
probability that the hours spent on the home computer by the participant are between 5.5 and
9.5 hours per week.
computers. In the survey, the number of hours was normally distributed, with a mean of 8
hours and a standard deviation of 1 hour. A survey participant is randomly selected. Find the
probability that the hours spent on the home computer by the participant are between 5.5 and
9.5 hours per week.
Answers
Answered by
PsyDAG
Z = (score-mean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to your Z scores.
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to your Z scores.
Answered by
Anonymous
0.3258
Answered by
Anonymous
Z-scores: (9.5-8)/1=1.5 and (5.5-8)/1=-2.5. Corresponding probabilities: 94.41%
and 0.62%, so the answer is P=94.41%-0.62%=93.79%
and 0.62%, so the answer is P=94.41%-0.62%=93.79%
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