Asked by Anonymous
A sample of air from the basement of a home is found to
contain 8.3 ppm of radon. What is the partial pressure of radon
in the basement if the total pressure is 755 torr?
contain 8.3 ppm of radon. What is the partial pressure of radon
in the basement if the total pressure is 755 torr?
Answers
Answered by
DrBob222
I assume that is 8.3 ppm v/v; if so I would convert that to percent.
(8.3E-6 L/10^6 L)* 100 = mole percent = about 8.3E-10%. Convert that to a fraction (divide by 100) to give mole fraction Rn_, then
p<sub>Rn</sub> = X<sub>Rn</sub>P<sub>total</sub>
(8.3E-6 L/10^6 L)* 100 = mole percent = about 8.3E-10%. Convert that to a fraction (divide by 100) to give mole fraction Rn_, then
p<sub>Rn</sub> = X<sub>Rn</sub>P<sub>total</sub>
Answered by
DrBob222
I erred here. 8.3 ppm should be expressed as 8.3E-6 mole fraction Rn.
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