Asked by John

sgr2 sinD cosD=sinD
Answered by Steve
If you're trying to solve

sqrt(2) sinD cosD = sinD

sinD(sqrt(2) cosD - 1) = 0

sinD = 0 means that D=0 + k*pi for any integer k will work.

cosD = 1/√2 means that D=2k*pi ± pi/4 will also work.
Answered by John
So:

47
137
227
317

Do I need to add +360n?
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