f(x)=ln(abc)=lna + lnb + lnc
f'(x)=1/a da/dx + 1/b (db/dx) + 1/c (dc/dx)
Go for it.
Find f'(x) if f(x) = ln [x^8 (x+9)^2 (x^2 + 5)^4 ]
Thank you very much for your help.
2 answers
THANK YOU SO MUCH! =)
Thank you very much for your help.
2 answers