Asked by Christian
1. Write a polynomial in standard form that has solutions: 0, -2, 3
2. Write a trinomial that has a degree of 4 and a lead coefficient of -3
3. True of false: 3/x^2 is a polynomial expression
2. Write a trinomial that has a degree of 4 and a lead coefficient of -3
3. True of false: 3/x^2 is a polynomial expression
Answers
Answered by
Count Iblis
1. Write a polynomial in standard form that has solutions: 0, -2, 3:
x(x+2)(x-3)
Expand this to write it in standard form.
x(x+2)(x-3)
Expand this to write it in standard form.
Answered by
Christian
So the answer would be x^2+2x-6 for #1?
Answered by
Damon
x^2 + 2 x - 6 is not correct
x(x+2)(x-3) is going to have an x^3 in it for starters
Multiply that all out more carefully.
x(x+2)(x-3) is going to have an x^3 in it for starters
Multiply that all out more carefully.
Answered by
Count Iblis
x(x+2)(x-3) =
x (x^2 - x - 6) =
x^3 - x^2 - 6 x
x (x^2 - x - 6) =
x^3 - x^2 - 6 x
Answered by
Christian
Ok I see my mistakes on #1. Thanks for the help.On #3 I don't think it is a polynomial but I'm not sure. Can anyone help with #2?
Answered by
Damon
I am sure. Negative powers of x are not allowed in the definition of polynomial.
write an expression with three terms
the first term, with the highest power of x has a coef of -3
That highest power of x is 4
the other two terms can have x^3, x^2, x^1 (which is x) and x^0 (which is one)
write an expression with three terms
the first term, with the highest power of x has a coef of -3
That highest power of x is 4
the other two terms can have x^3, x^2, x^1 (which is x) and x^0 (which is one)
Answered by
Christian
What do you mean negative powers of x? The expression is 3 over x squared. But it isn't a polynomial expression right?
Answered by
Damon
3/x^2 = 3 x^-2
Answered by
Christian
Thanks. For #2 can it be 5x^4+2x^3+7x^2+4x+1? Promise I'm done asking after this!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.