Question

~I got a and b right but c i can't figure out

Freight trains can produce only relatively small acceleration and decelerations.

(a) What is the final velocity of a freight train that accelerates at a rate of 0.0600 m/s2 for 8.00 min, starting with an initial velocity of 5.00 m/s?

33.8 m/s

(b) If the train can decelerate at a rate of 0.550 m/s2, how long will it take to come to a stop from this velocity?

61.45 s

(c) How far will it travel in each case?
m (distance traveled during acceleration)
m (distance traveled during deceleration)

Answer 1

Vf^2=Vi^2+2ad

in each case, you know vf, vi, a (one them it is negative, solve for d)

or, you can figure average velocity (avg velocity= 1/2(Vf+vi), and distance= avgvelocty*timeinseconds

Answer 2

i don't understand what ad is