Vf^2=Vi^2+2ad
in each case, you know vf, vi, a (one them it is negative, solve for d)
or, you can figure average velocity (avg velocity= 1/2(Vf+vi), and distance= avgvelocty*timeinseconds
~I got a and b right but c i can't figure out
Freight trains can produce only relatively small acceleration and decelerations.
(a) What is the final velocity of a freight train that accelerates at a rate of 0.0600 m/s2 for 8.00 min, starting with an initial velocity of 5.00 m/s?
33.8 m/s
(b) If the train can decelerate at a rate of 0.550 m/s2, how long will it take to come to a stop from this velocity?
61.45 s
(c) How far will it travel in each case?
m (distance traveled during acceleration)
m (distance traveled during deceleration)
2 answers
i don't understand what ad is