Asked by Sparkles
2 Long vertical walls are separated by length l. A ramp is placed between the walls as shown below. A block is placed on the ramp and one end and slides without friction towards the other end. Find the ramp angle (theta) which results in the fastest trip from one end of the ramp to the other. use g as a constant
Answers
Answered by
drwls
Ramp length = L/cosA
Acceleration rate = g sin A
Trip time = sqrt (2L/a)
= sqrt(2L^2/(g*sinAcosA]
= 2L*sqrt(1/sin(2A)]
That is a minimum 2A = 90 degrees
A = 45 degrees
Acceleration rate = g sin A
Trip time = sqrt (2L/a)
= sqrt(2L^2/(g*sinAcosA]
= 2L*sqrt(1/sin(2A)]
That is a minimum 2A = 90 degrees
A = 45 degrees
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.