Asked by gaston
Design a carnival ride on which standing passengers are pressed against the inside curved wall of a rotating vertical cylinder. It is to turn at most at 1/7 revolution per second. Assuming a minimum coefficient of friction of 0.10 between clothing and wall, what diameter should the ride have if we can safely make the floor drop away when it reaches running speed?
Answers
Answered by
winner
r = vt / (2*pi)
r = (1/7)v/(2*pi)
r =~ 0.0227364v
μ = v^2 /rg
0.1 = v^2 /9.8*r
0.98 = v^2 / 0.0227364v
v's cancel and left with
0.98 = v / 0.0227364
then solve for V
r = (1/7)v/(2*pi)
r =~ 0.0227364v
μ = v^2 /rg
0.1 = v^2 /9.8*r
0.98 = v^2 / 0.0227364v
v's cancel and left with
0.98 = v / 0.0227364
then solve for V
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