Question

In a city with no cars of mixed color, 30% of the cars on the road are brown. Forty percent are either brown or green, and 10% are white.
a.) What is the probability that a randomly selected car is green?

b.) What is the probability that a randomly selected car is not brown, green, or white?


Thanks a bunch for whoever can help!?

Answer 1

How many cars were there altogether?

Answer 2

It doesn't say how many cars in total there were. Im guessing that in total these cars added up to 100%.

Answer 3

a.)1/5
b.)1/4

Answer 4

Is there anyway that you can show me how you got that so I can understand a little better? Thanks!

Answer 5

a.)40% of cars are either brown or green. Divide that by two since there are two colors. You get 20. Put that over 100=20/100. Reduce it to 2/10 which reduces to 1/5.
b.)Add all the percents together to get 80%. Subtract it from 100. 100-80=20. 20/100=1/5. So the actual answer to b is 1/5. Sorry, my mistake. :P

Answer 6

Thanks a bunch!

Answer 7

No problem.(:

Answer 8

What about the undefined remaining 20%?

30% + 40% + 10% = only 80%

Answer 9

She DID do that.