Asked by jason
A diver in midair has an angular velocity of 6.0 rad/s and a moment of inertia of 1.2 kg·m2. He then pulls is arms and legs into a tuck position and his angular velocity increases to 12 rad/s. The net external torque acting on the diver is zero. What is his moment of inertia in the tuck position?
Answers
Answered by
genius girl
The Conservation of Angular Momentum will be conserved. (Hint: it states that the net external torque acting on the diver is zero.)
Angular Momentum =
moment of inertia x angular velocity
(6.0) (1.2) = 12x
7.2 = 12x
x = 0.6 kg·m^2
Angular Momentum =
moment of inertia x angular velocity
(6.0) (1.2) = 12x
7.2 = 12x
x = 0.6 kg·m^2
Answered by
Autard
Ur dumb :3
Answered by
LL
0.6
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