Use -3mg=mg-mv^2/r. M cancels out
so..-3g=g-v^2/r. then solve for r algebraically
I tried the equation
r=v^2/m*gr=27^2/3*9.81, but I keep getting it wrong. Please help!
so..-3g=g-v^2/r. then solve for r algebraically
In this case, the normal force on the roller coaster is three times its weight, which means that the normal force is three times the gravitational force acting on the roller coaster.
First, let's find the weight of the roller coaster. The weight is given by the equation:
Weight = mass * gravitational acceleration
Next, since the normal force is three times the weight, we can write:
Normal force = 3 * Weight
Now, let's calculate the weight of the roller coaster. We need to know the mass of the roller coaster, which is not given in the question. Assuming that we have the mass, we can substitute it into the equation to find the weight.
Once we have the weight, we can calculate the normal force using the equation above.
Finally, we can use the relationship between centripetal force, the normal force, and the radius of curvature to find the radius. The centripetal force is given by the equation:
Centripetal force = (mass * velocity^2) / radius
In this case, the centripetal force is equal to the normal force, so we can write:
Normal force = (mass * velocity^2) / radius
Rearranging the equation to solve for the radius, we get:
Radius = (mass * velocity^2) / normal force
Substituting the values we obtained for the mass, velocity, and normal force into the equation, we can find the radius of curvature.