Asked by sasi
a magnetic crane left a mass 1500 through a vertical height of 40m.calculate the work done in operating the crane
Answers
Answered by
drwls
W= M*g*H
The mass M is presumably 1500 kg
g = 9.8 m/s^2
Do the multiplication.
Work W will be in Joules with these units
The mass M is presumably 1500 kg
g = 9.8 m/s^2
Do the multiplication.
Work W will be in Joules with these units
Answered by
ishv
F=m*g
=1500*9.8=14700N
w=f*s
=14700*40
=58800J
=1500*9.8=14700N
w=f*s
=14700*40
=58800J
Answered by
Ved
Mass(cm)=1500kg
Displacement (s)=-40m
g=9.8m/s^2
To find
W=F*S
F=mg
F=1500*9.8
F=14700
W=F*S
=14700*(-40)
=-588000
=-588*10^3J
The work is done in operating the crane is= [-588*1035]
Displacement (s)=-40m
g=9.8m/s^2
To find
W=F*S
F=mg
F=1500*9.8
F=14700
W=F*S
=14700*(-40)
=-588000
=-588*10^3J
The work is done in operating the crane is= [-588*1035]
Answered by
Adki
Why minus 40
Answered by
Smartie Boi
You have to multiply the height or distance x gravitational pull x weight
formula:
W= h (or d for distance) x g x w
W= 40 x 9.81 x 1500
W= 588600J
the work being done is 588600 Joules
formula:
W= h (or d for distance) x g x w
W= 40 x 9.81 x 1500
W= 588600J
the work being done is 588600 Joules
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