Asked by Aubrey
Totally confused-learned this today and I don't get it-Please help
Write the standard form of 9x^2 + 4y^2-72x+16y+124=0
I think the first step is to take the constant to right side so I have:
9x^2 + 4y^2-72x+16y=124
But then I'm lost!
Write the standard form of 9x^2 + 4y^2-72x+16y+124=0
I think the first step is to take the constant to right side so I have:
9x^2 + 4y^2-72x+16y=124
But then I'm lost!
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