Asked by Hannah

In the cchemistry lab we conducted an experiment called atomic spectroscopy.
We had to find the color, energy, wavelength, and 1/lamda for Hydrogen, neon, and mercury.

For hydrogen:
red 1.90ev 650nm 1.54e^-3
red 2.02ev 610nm 1.64e^-3
green 2.30ev 545nm 1.83e^-3

for neon:
green 2.30ev 550nm 1.82e^-3
red 2.05ev 610nm 1.64e^-3
red 1.80ev 690 1.45e^-3
yellow 2.12 580 1.72e^-3
blue 2.65 470 2.13e^-3

for mercury:
green 2.30ev 548 1.823^-3
red 2.05 590 1.69e^-3
violet 2.85 440 2.27e^-3
blue 2.55 470 2.13e^-3
yellow 2.15 570 1.75e^-3

for the first question we had to derive the equation that would allow us to find Planck's constant from your graph using the formulas
c= lamda X v and E=hv


The teacher said that the equation is h=slope / c

The next question says to show the calculations of Planck's constant, including the unit conversions, for mercury, neon, and hydrogen using the equation created above.

I am not sure how to do this. I do not know where to start.

We had to create graphs for neon and hydrogen on the computer so would i use the slope from there?
Answered by DrBob222
What were your axes? What did you plot on the x axis and what on the y axis?
The slope is delta y/delta x.
Answered by Hannah
on the x axis was 1/wavelength (nm-1) and the y axis was energy(ev). The line for both graphs of neon and hydrogen was positive. So would I pick two points on the graph to find the slope and then do h=slope/c?
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