Asked by Anon
A person suffering from hyponatremia has a sodium ion concentration
in the blood of 0.118 Mand a total blood volume of
4.6 L.What mass of sodium chloride would need to be added
to the blood to bring the sodium ion concentration up to
0.138 M, assuming no change in blood volume?
in the blood of 0.118 Mand a total blood volume of
4.6 L.What mass of sodium chloride would need to be added
to the blood to bring the sodium ion concentration up to
0.138 M, assuming no change in blood volume?
Answers
Answered by
DrBob222
How many moles Na^+ do we want? That is M x L = 4.6L x 0.138M = ?
How many moles do we have? That is M x L = 4.6L x 0.118M = x
The difference is ?-x = z moles Na^+
Convert z moles Na^+ to moles NaCl (to give z moles NaCl), then
grams = moles x molar mass NaCl.
How many moles do we have? That is M x L = 4.6L x 0.118M = x
The difference is ?-x = z moles Na^+
Convert z moles Na^+ to moles NaCl (to give z moles NaCl), then
grams = moles x molar mass NaCl.
Answered by
h
.092