Question

Using a spring gun, a 4.0-kg steel block is launched up a lubricated ramp made out of steel. The angle of the ramp was measured to be 38.8ยบ. The inital speed of the block was 12.0 m/s.

(a) Determine the vertical height that the block reaches above its launching point.
(b) What speed does the block have when it sldes back to its startin point?
Vo = 12m/s @ 38.8 Deg.
Xo = 12cos38.8 = 9.35m/s.
Yo = 12sin38.8 = 7.5m/s.

a. h = (Yf^2 - Yo^2) / 2g,
h = (0 - (7.5)^2) / -19.6 = 2.88m.

b. Yf^2 = Yo^2 + 2g*d,
Yf^2 = 0 + 19.6*2.88 = 56.4,
Yf = 7.5m/s.

Related Questions

A child's toy consists of a block that attaches to a table with a suction cup, a spring connected to... A child's game consists of a block that attaches to a table with a suction cup, a spring connect... A 50 gram block is placed on a frictionless ramp 2 meters above the ground. It slides down the ramp... A 200 g block is pressed against a spring with a spring constant of 1.4 kN/m until the block compre...