Asked by DJ
(y/(x+9y))= (x^2)-7
at the point (1, -6/55)
Use implicit differentiation to find the slope of the tangent line to the curve
at the point (1, -6/55)
Use implicit differentiation to find the slope of the tangent line to the curve
Answers
Answered by
Reiny
cross-multiply first
y = x^3 - 7x + 9x^2y - 63y
y' = 3x^2 - 7 + 9x^2y' + 18xy - 63y' , where y' = dy/dx
64y' - 9x^2y' = 3x^2 + 18xy-7
y' = dy/dx = (3x^2 + 18xy - 7)/(64 - 9x^2)
I will leave it up to you to do the remaining arithmetic
y = x^3 - 7x + 9x^2y - 63y
y' = 3x^2 - 7 + 9x^2y' + 18xy - 63y' , where y' = dy/dx
64y' - 9x^2y' = 3x^2 + 18xy-7
y' = dy/dx = (3x^2 + 18xy - 7)/(64 - 9x^2)
I will leave it up to you to do the remaining arithmetic
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.