Asked by DJ
f(x)= 6ln(2x+7ln(x)) I need to find the first derivative.
Answers
Answered by
Steve
f = 6 ln(2x + 7lnx)
f = 6ln(u(x))
df/dx = 6/u * du/dx
f' = 6 * 1/(2x + 7lnx) * (2 + 7/x)
f = 6ln(u(x))
df/dx = 6/u * du/dx
f' = 6 * 1/(2x + 7lnx) * (2 + 7/x)
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