90.0 of is initially at room temperature (22.0). A chilled steel rod at 2.0 is placed in the water. If the final temperature of the system is 21.3, what is the mass of the steel bar?

Question

Specific heat of water = 4.18

Specific heat of steel = 0.452

Answer 1

The sume of the heats gained is zero (some heats gained are negative). Because I cannot read the units above,

masswater*cw*(21.3-22)+masssteel*csteel*(21.3-2)=0
solve for mass steel