Asked by Liz
Suddenly losing his thirst, Mathman decides to check out the festivities, but just then, Frankenstein ran by him screaming, "Cheater, cheater, apple eater." It seems that Dracula had illegally been using his bicuspids to win at apple-bobbing. Frankenstein was furious and ran outside with the apple. He then heaved it skyward at a rate of 192 feet per second. If he released the apple at a height of 10 feet, how high did the apple go? When did it return to the ground?
Thanks
Thanks
Answers
Answered by
Steve
h = 10 + 192t - 16t^2
This reaches its peak at t = -192/-32 = 6
h(6) = 586 feet
h = 0 when t = 12.05 sec
This reaches its peak at t = -192/-32 = 6
h(6) = 586 feet
h = 0 when t = 12.05 sec
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.