Asked by Kelsey
An object is thrown straight upwards from the ground at 28 m/s. Due to air resistance (a non-conservative force), the object loses 31.4 percent of its initial energy during its trip to reach maximum height. How much higher does the object travel if there was no air resistance? Answer in meters.
Answers
Answered by
Henry
Vo = 28m/s with no air resistance.
h1 = (Vf^2 - Vo^2) / 2g,
h1 = (0 - (28)^2) / -19.6 = 40m.
Vo = 28 * (100%-31.4%)/100% = 18.452m/s
with air res.
h2 = (0 - (18.452)^2) / -19.6 = 17.4m.
h=hi - h2 = 40 - 17.4 = 22.63m. higher
with no air res.
h1 = (Vf^2 - Vo^2) / 2g,
h1 = (0 - (28)^2) / -19.6 = 40m.
Vo = 28 * (100%-31.4%)/100% = 18.452m/s
with air res.
h2 = (0 - (18.452)^2) / -19.6 = 17.4m.
h=hi - h2 = 40 - 17.4 = 22.63m. higher
with no air res.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.