Asked by Anonymous
An autographed baseball rolls off of a 0.82 m
high desk and strikes the floor 0.28 m away
from the desk.
How fast was it rolling on the desk before
it fell off? The acceleration of gravity is
9.81 m/s
2
high desk and strikes the floor 0.28 m away
from the desk.
How fast was it rolling on the desk before
it fell off? The acceleration of gravity is
9.81 m/s
2
Answers
Answered by
drwls
0.28 m = (horizontal velocity component)*(fall time)
The fall time is sqrt(2H/g) = 0.4089 s
H = 0.82 m
Solve for the horizontal velocity component
0.685 m/s
The fall time is sqrt(2H/g) = 0.4089 s
H = 0.82 m
Solve for the horizontal velocity component
0.685 m/s
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