Asked by ...........
if b is a real number satisfying b^4 + 1/(b^4) = 6, find the value of :-
(b + i/b)^16 where i = sqrt of -1
(b + i/b)^16 where i = sqrt of -1
Answers
Answered by
Writeacher
Your umpteen posts have been removed.
Once you write up <b>WHAT YOU HAVE TRIED TO SOLVE EACH PROBLEM</b>, please re-post, and someone here will be happy to comment.
Once you write up <b>WHAT YOU HAVE TRIED TO SOLVE EACH PROBLEM</b>, please re-post, and someone here will be happy to comment.
Answered by
Juboraj
(b)^4+(i/b)^4=6 and
then use (a^2+1/a^2)=(a+1/a)^2-2 multiple times
(b+i/b)^16=4096
then use (a^2+1/a^2)=(a+1/a)^2-2 multiple times
(b+i/b)^16=4096
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