Asked by Luke
Find two positive numbers that satisfy the given requirements.
The product is 147 and the sum of the first number plus 3 times the second number is a minimum.
The product is 147 and the sum of the first number plus 3 times the second number is a minimum.
Answers
Answered by
Steve
a*b = 147
147 = 3*7*7
So, the only choices for a*b are
3*49
49*3
7*21
21*7
1*147
147*1
You can figure which gives minimum a+3b
147 = 3*7*7
So, the only choices for a*b are
3*49
49*3
7*21
21*7
1*147
147*1
You can figure which gives minimum a+3b
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