Question
y+2=10-y, (with a radical root sign over the y+2)
Answers
Henry
sqrt(y+2) = 10 - y,
Square both sids:
y+2 = 100 -20y + y^2,
y^2 - 20y - y = 2 -100,
y^2 - 21y = -98,
y^2 - 21y + 98 = 0,
(y-14)(y-7) = 0,
y-14 = 0,
Y = 14.
y-7 = 0,
Y = 7.
Solution Set: Y = 7, and 14.
Square both sids:
y+2 = 100 -20y + y^2,
y^2 - 20y - y = 2 -100,
y^2 - 21y = -98,
y^2 - 21y + 98 = 0,
(y-14)(y-7) = 0,
y-14 = 0,
Y = 14.
y-7 = 0,
Y = 7.
Solution Set: Y = 7, and 14.