Asked by -Untamed-
In triangle PQR, angle P is 20 degres, angle R is 150 degrees, and QR is 6, the length of PQ is...?
Answers
Answered by
Reiny
simple application of the sine law
PQ/sin150 = 6/sin20
PQ = 6sin150/sin20
= ....
PQ/sin150 = 6/sin20
PQ = 6sin150/sin20
= ....
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