Asked by tracy
Solve the equation. Check both solutions and only write the real solution.
the square root of 6m minus 5 = m
A. {1}
B. {5}
C. {1, 5}
D. no real solution
I think its B
the square root of 6m minus 5 = m
A. {1}
B. {5}
C. {1, 5}
D. no real solution
I think its B
Answers
Answered by
Reiny
√(6m) - 5 = m
√(6m) = m+5
square both sides
6m = m^2 + 10m + 25
m^2 + 4m + 25 = 0
m = (-4 ± √-84)/2
no real solution
if you think it is B), why not check it
LS = √30 - 5
RS = 5
mmmhhh
<b>However</b>, if you meant:
√(6m-5) = 5
then 6m-5 = 25
6m = 30
m = 5
See what happens if you don't use brackets to avoid ambiguity?
√(6m) = m+5
square both sides
6m = m^2 + 10m + 25
m^2 + 4m + 25 = 0
m = (-4 ± √-84)/2
no real solution
if you think it is B), why not check it
LS = √30 - 5
RS = 5
mmmhhh
<b>However</b>, if you meant:
√(6m-5) = 5
then 6m-5 = 25
6m = 30
m = 5
See what happens if you don't use brackets to avoid ambiguity?
Answered by
Afeez
U tried bt itz wrong . .ansa iz a . . 6m - 5 =m . Colect lyk terms . 6m -m =5 . 5m =5 . Then m =1 .
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