Asked by Hellga
Please explain the steps on to solve this equation.
x^-6 - 8x^-3 + 16 = 0
k^-4/3 - 10k^-2/3 + 21 = 0
x^-6 - 8x^-3 + 16 = 0
k^-4/3 - 10k^-2/3 + 21 = 0
Answers
Answered by
Count Iblis
x^-6 - 8x^-3 + 16 = 0
Put x^(-3) = y. Then:
y^2 - 8 y + 16 = 0 --->
(y - 4)^2 = 0 --->
y = 4 ---->
x = 4^(-1/3) = 2^(-2/3)
Put x^(-3) = y. Then:
y^2 - 8 y + 16 = 0 --->
(y - 4)^2 = 0 --->
y = 4 ---->
x = 4^(-1/3) = 2^(-2/3)
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